a constant force F=(m2g)/2 is applied on the block of mass m1?as shown in figure. the string and pulley are light and surface of the table is smooth. find the acceleration of m1

M1 is placed on a horizontal surface, pulley is at the corner and m2 is hanging
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F - T(tension)=m1a
T-m2g=m2a
add both
F- m2g= m1a=m2a
F-m2g=(m1+m2)a
F=m2g/2[given]
m2g/2-m2g=(m1+m2)a
-m2g/2=(m1+m2)a
a = -m2g/2(m1+m2)
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A constant force F = m2 g/2 is applied on the block of mass m1 as shown in fig. The string and the pulley are light and the surface of the table is smooth. The acceleration of m1 is –
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A constant force  =  2  is applied on the block of mass  1 as shown in the figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of  1 .
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Please find this answer

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