A contractor employed 210 men to build a house in 60 days . After 12 days , he was joined by 70 more men. in how many days willthe remaining worh be finished?

no.of days taken by 210 men to complete the full work =60 days

work completed in 12 days = 1/5 of full work

no. of days taken by 210 men to complete (4/5 of full work)# =60-12=48 days

no. of days taken by 1 man to complete 4/5 of full work=210*48

no. of days taken by (210+70)=280 men to complete 4/5 of full work=210*48/280=36 days

#4/5 of the full work refers to the remaining work to be completed.

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210 * 48 = 280 x

x =210 * 48  / 280

x = 36

Ans: 36 days

  • -1

AFTER 12 DAYS , THE REMAINING PART OF THE WORK CAN BE COMPLETED BY 210 MEN IN ( 60 - 12 ) = 48 DAYS . LET THE SAME WORK BE COMPLETED BY ( 210 + 70 ) = 280 MENS IN X DAYS .

 MENS    DAYS

 210   ( 60 -12 =) 48

 ( 210 + 70 = ) 280  X

THIS IS INDIRECT VARIATION

210 * 48 = 280 * X

X = 210 * 48  /  280

X = 36 DAYS

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