A convex lens is placed between an object and a screen which are fixed a distance D apart. For one position of lens the magnification of the sharp image is m1.when the lens is moved through d, the magnification of the image is m2. Focal length of the lens is A) d/m1 - m2  B) d/m1+m2 C) m1 + m2 / d  

Answer is d/m1-m2. Hope this helps!!!!!😃😃

  • 1
What are you looking for?