A convex mirror of focal length 20cm produces a magnification 1/2times of an object of size 8cm. Find the change in size of the image if the focal length of the mirror increases to 40cm?

Mirror equation:1f=1u+1vCase I:Magnification,m=-vu12=-vuu=-2vHence,1-20=1-2v+1v1-20=12vv=-10 cmu=-2×-10=20 cmhiho=-vuhi=--1020×8=4 cmCase II:1-40=120+1v1v=-140-120     =-340v=-13.3 cmhiho=-vuhi=--13.320×8=5.32 cmChange in size of the image=5.32 - 4=1.32 cm

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