a couple of moment 200/pie dyne cm produces 2 revolutions per second in a body.calculate the work done during two revolutions.

Dear student 
The work done W = F.s
momemt of force is torque =200/pie dyne cm
   no.of revolution n = 2
for rotational  motion 
$$\begin{gathered} W = F.r.\theta \\ =\tau .\theta \\ =\tau .2\pi n \\ =\frac{200}{\pi }\times 2\times 2\times \pi \\ W = 800 dyne cm radian \end{gathered}$$
Regards