A cricket team of 11 players is to be chosen from 16 players which includes 5 bowlers and 2 wicket keepers. How many ways can a team be selected if each team must have 3 bowlers and 1 wicket keeper?? Plzzz answer!!

out of 16 players , number of bowlers = 5 and the number of wicket keepers = 2

others = 16-(5+2)=9

now the required selection can be done in following manner:

$\underset{\left(i\right)case}{3B+1W+7Ot}or\underset{\left(ii\right)case}{3B+2W+6Ot}or\underset{\left(iii\right)case}{4B+1W+6Ot}or\underset{\left(iv\right)case}{4B+2W+5Ot}\phantom{\rule{0ex}{0ex}}or\underset{\left(v\right)case}{5B+1W+5Ot}or\underset{\left(vi\right)case}{5B+2W+4Ot}$

$={}^{5}C_{3}.{}^{2}C_{1}.{}^{9}C_{7}+{}^{5}C_{3}.{}^{2}C_{2}.{}^{9}C_{6}+{}^{5}C_{4}.{}^{2}C_{1}.{}^{9}C_{6}+\phantom{\rule{0ex}{0ex}}{}^{5}C_{4}.{}^{2}C_{2}.{}^{9}C_{5}+{}^{5}C_{5}.{}^{2}C_{1}.{}^{9}C_{5}+{}^{5}C_{5}.{}^{2}C_{2}.{}^{9}C_{4}\phantom{\rule{0ex}{0ex}}=10*2*36+10*1*84+5*2*84+5*1*126+1*2*126+1*1*126\phantom{\rule{0ex}{0ex}}=720+840+840+8*126\phantom{\rule{0ex}{0ex}}=2400+1008\phantom{\rule{0ex}{0ex}}=3408$

hope this helps you

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