A cube of side 5cm is immersed in water and then in saturated salt solution. In

which case will it experience a greater buoyant force. If each side of the cube is

reduced to 4cm and then immersed in water compare the force experienced by the

cube, as compared to the first case. Give reasons for each case.

When a person is floating on the liquid the net buoyant force = weight of the liquid displaced( Vρg )

or 5^{3} cm^{3}

ρ is density of the liquid.

So, if the density water is more then the buoyant force is more. So, the buoyant force is more in the case of saturated salt solution due to greater density then water.

If each side of cube is reduced and then immersed in water, buoyant force will also decrease by above given relation

So, the net buoyant force becomes = V'ρg

where V' be the new volume, V = 64 cm^{3.}

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