A cube of size 10 cm is floating in equilibrium in a tank of water When a mass of - Science - Gravitation

Question

A cube of size 10 cm is floating in equilibrium in a tank of water
When a mass of 10 gm is placed on the cube , the depth of cube
inside water increases by(g=10 m/s2 ,density of water=
1000 kg/m3)

a) 0 1 mm b) 1 m c) 1 mm d) 0 1 m please explain answer in detail

Govind · Accepted Answer

Hi,

Let x be the initial depth upto which the cube is sinked in water
 Let d be thedensity of the cube
Thenx×10×10×1×g=10×10×10×d×g     
1    ∵ mass=volume×density⇒x=10dLet x' be the new depth, thenx'×100×g=1000×d×g+10g     
2Subtracting 1 from 2, we get⇒100x'=100x+10      
⇒x'-x=110 cm=1 mm

A cube of size 10 cm is floating in equilibrium in a tank of water. When a mass of 10 gm is placed on the cube , the depth of cube inside water increases by(g=10 m/s2 ,density of water= 1000 kg/m3) a) 0.1 mm b) 1 m c) 1 mm d) 0.1 m please explain answer in detail.

A cube of size 10 cm is floating in equilibrium in a tank of water. When a mass of 10 gm is placed on the cube , the depth of cube inside water increases by(g=10 m/s^{2 ,}density of water= 1000 kg/m³)

a) 0.1 mm b) 1 m c) 1 mm d) 0.1 m please explain answer in detail.