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a cubical block of side 14 cm is surmounted by a hemisphere of  maximum diameter.  find the surface area of the solid​

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diameter=14
radius=7

        area of solid = tsa of cube + csa of hemisphere - pir​2
                               6l2 +2pir2 - pir​2
                                6(14*14) +  pir​2
                                    6(196) + 22/7*7*7
                              1176 + 154
                             1330cm2
 
 
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area of solid = T.S.A of cube + C.S.A of hemisphere - pi(r2)
                     =  6a2 + 2 pi (r2) - pi(r2)
                    =6( 14 2) + pi (r2)
                    =6(196) + 22 (7)(7)
                                       7
                    =1176 + 154
                   = 1330 cm3

 
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max diameter is 14
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