A cubical vessel has a side with'1'cm length contained a pressure 'p'when.the side of the vessel is made 1/2cm ,the pressureofthe gas becomes
Pressure =Force \Area
Let force be F
Now, pressure =F\1²=F
If sides 1\2, then area =1\4
Therefore , pressure = F\1\4 = 4F
Therefore pressure is 4times the original one