a current carrying circular coil of radius 6.28cm is placed with its plane in magnetic maridian.the resultant magnetic maridian.the resultant magnetic induction at the center of the coil is[given current in the coil is 3a and Bh=0.4 gauss]

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As the coil is placed in the magnetic meridian so earth magnetic field  say B1 lies in the earth magnetic field.And magnetic field of inducion due to current in the coil say B2 is perpendicular to theplane ofthe loop.Bnet=B21+B22B1=0.4gauss=0.4×10-4T=4×10-5TB2=μ4π×IR×2π=10-7×36.28×10-2×(6.28)B2=0.3×10-4=3×10-5TBnet=B21+B22Bnet=(4)2+(3) ×10-5Bnet=5×10-5TRegards

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