A current is passed through 2 voltmeters connected in series. The first voltmeter contains XSO4(aq.)and second has Y2SO4the relative atomic masses of X and Y are in the ratio of 2:1. What is The ratio of the mass of X liberated to the mass of Y ?

Dear Student,Ratio of relative atomic masses of X and Y = 2:1 oxidation state of X in XSO4 = +2 oxidation state of Y inY2SO4 =+1Equivalent Mass =Mass of Metaloxidation state of metal atom Mass of X liberated = mxMass of Y liberated = mYRelative mass of X is represent by MxRelative mass of Y is represent by MyThe ratio of given  atomic masses is equal to the ratio of equivalent masses of X and YmxmY=ExEymxmY=Mx/2My/1mxmY=21×12mxmY=11mx: mY= 1:1Regards

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