A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 - Science - Electricity

Question

A current of 1 ampere flows in a series circuit containing
an electric lamp and a conductor of 5  when connected to
a 10 v battery Calculate the resistance of the electric lamp Now if
a resistance of 10  is connected in parallel with this
series combination, what change (if any) in current flowing through
5  conductor and potential difference across the lamp
will take place? Give reason Draw circuit diagram

Hansraj Rai · Accepted Answer

Dear Student!!

B is lamp When both are connected in series, I = 1 A Using Ohm's law, $V = I (R) R = R_{L} + R_{C} R_{L} + R_{C} = \frac{V}{I} = 10 g i v e n, R_{C} = 5 Ω R_{L} = 10 - 5 = 5 Ω$ is the resistance of the lamp when a 10 ohm resistance is connected in parallel, Total resistance is , $\frac{1}{R'} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10} R' = 5 Ω$ Current in parallel connection, $V = I' R' I' = \frac{V}{R'} = \frac{10}{5} = 2 A$ Current through the first branch will remains same as V is same Voltage across the lamp will not change