A cylindrical block of radius "r" and mass "m" is lying on the table. If its radius is d oubled and mass is tripled then what happens to pressure acting on the table.??
Given that,
The radius of the cylinder =r and mass =m
So its weight W = mg
Area of cross-section, A = πr2
So, pressure, P = mg/(πr2)
Now, when the radius is doubled and mass is tripled, then pressure,
P/ = (3m)g/[π(2r)2] = (3/4)mg/(πr2) = (3/4)P = 0.75P
Thus the pressure decreases and becomes 0.75 times the initial pressure.