a cylindrical block of radius r and mass m is lying on the table. if the radius is doubled and mass is tripled then what happens to pressure acting on the table
pressure P=force/area=mg/πr2
when radius doubled and mass tripled.
pressure=force/area=3mg/π(2r)2
=3mg/4πr2=3P/4
pressure after changing radius and mass become 3/4 times the initial pressure.