# A dice is thrown 30 times how many times do you expect the number 6 to be appear on the top

$Probabilityofgettingasixinathrowofdice=\frac{Numberoffavourableoutcomes}{Totalnumberifoutcomes}=\frac{1}{6}\phantom{\rule{0ex}{0ex}}Numberofsixesobtainedin30throws=30\times \frac{1}{6}=5$

Since it is probability, one can never be sure.

Regards

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