a die has 6 faces marked 0,1,1,1,6,6. Two such dies are thrown together and the total score is recorded.
(1) How many different scores are possible?
(2) What is the probability of getting a total of 7?
 

(1) Two such dies are thrown simultaneously, the possible outcomes are -:
              (0,0) (0,1) (0,1) (0,1) (0,6) (0,6)
              (1,0) (1,1) (1,1) (1,1) (1,6) (1,6)
              (1,0) (1,1) (1,1) (1,1) (1,6) (1,6)
              (1,0) (1,1) (1,1) (1,1) (1,6) (1,6)
              (6,0) (6,1) (6,1) (6,1) (6,6) (6,6)
              (6,0) (6,1) (6,1) (6,1) (6,6) (6,6)
Thus, the possible no. of outcomes are 36.
(2) Let E be event of getting a total of 7.
Then, the outcomes favourable to event E are -: (1,6) (1,6) (1,6) (1,6) (1,6) (1,6)  (6,1) (6,1) (6,1) (6,1) (6,1) (6,1)
No. of outcomes favourable to event E = 12
Therefore, P(E) = 12/36= 1/3