a die is thrown 400 times with the frequency for the out comes 1,2,3,4,5,6, given in the following table outcomes frequency 72,65,70,71,63,59. find the probablity of
1)geting a number less than 3
2)geting number more than 4

Total number of times a die is thrown = 400Total number of possible outcomes = 4001.Number of times '1' appears = 72Number of times'2' appears = 65Number of times a number less than 3 appears = 72 + 65 = 137Number of favourable outcomes = 137Required probability = Number of favourable outcomesTotal number of possible outcomes = 1374002.Number of times '5' appears = 63Number of times'6' appears = 59Number of times a number more than 4 appears = 63+59 = 122Number of favourable outcomes = 122Required probability = Number of favourable outcomesTotal number of possible outcomes = 122400 = 61200

  • 7
1) P( getting a number less than 3 )   =  72+65/400  =  72.1625
2) P ( getting a number more than 4 )  = 63+59/400  =  63.1475
  • -3
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