A die is thrown 600 times and the frequency for the outcomes 1,2,3,4,5 and 6 are given in the table below:-

Prove that the sum of the probablity of these events is 1.

Question

A die is thrown 600 times and the frequency for the outcomes
1,2,3,4,5 and 6 are given in the table below:-

Prove that the sum of the probablity of these events is 1

Rupak Bhattacharya · Accepted Answer

Total number of times a die is thrown = 600Total possible outcomes = 600Number of times '1' appears = 60Number of times '2' appears = 90Number of times '3' appears = 175Number of times '4' appears = 68Number of times '5' appears = 50Number of times '6' appears = 157Now, Pgetting 1 +Pgetting 2+ Pgetting 3+ Pgetting 4+ Pgetting 5+ Pgetting 6=60600 + 90600 + 175600 + 68600 + 50600 + 157600=60+90+175+68+50+157600=600600=1

A die is thrown 600 times and the frequency for the outcomes 1,2,3,4,5 and 6 are given in the table below:- Prove that the sum of the probablity of these events is 1.

A die is thrown 600 times and the frequency for the outcomes 1,2,3,4,5 and 6 are given in the table below:-

Prove that the sum of the probablity of these events is 1.