A die is thrown again and again until three sixes are obtained. Find the probability of obtaining the third six in the sixth throw of the die.?

pls xplain me the solution

Let the probability of obtaining a ‘six’ in a single throw of the die (p) = 1/6

Then, the probability of not obtaining a “six” in a single throw of the die (q) =1-p = 1-1/6 = 5/6

Obtaining third six in the sixth throw of the die means that in the first five throws there are 2 sixes and the third six is obtained in the sixth throw. Therefore,

Hence, probability of obtaining the third six in the sixth throw of the die is 625/23328.