A die is thrown once ​​.Find the probabilty of getting
a)A doublet
b)A doublet of primes
c)A total of nine
d)An odd number on first die and a multiple of 3 on second die

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Please find below the solution to the asked query:

Assuming that, "A die is thrown twice" not onceTotal cases=62=36i Doublet will be 1,1,2,2,3,3,4,4,5,5,6,6 i.e. 6 casesRequired probability=636=16ii A doublet of primes can be 2,2,3,3,5,5Required probability=336=112iii An odd number on first die and multiple of 3 on other =1,3,1,6,3,3,3,6,5,3,5,6 Required probability=636=16

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