a disc of radius r rolls on a horizontal surface with linear velocity vi and angular velocity w(-k). theres a particle p on the surface of the disc. which has a velocity in the vertical direction. the height of that particle from ground will be

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​Please ask your question in a meaning full way. I cannot  understand it. 
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Total tangential acceleration at=a+rαat=a+rα
Total radial axes ar=V2rar=V2r
=rw2=rw2
Hence a=at2+ar2−−−−−−−√

 
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