A disc rotating about its axis from rest. acquires the angular speed 100 rev/s in 4 second, The angle rotated by it during these four seconds (in radian) is ?

100rev/s =2π×100
->for 4s
2π×100×4
=800π radians

Ans given is 400 pi 
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Sahi to bhej

We are given that nu is equal to 100 Revolution per second Omega is equal to zero and finale is 2π×100=200π Angular acceleration is 200π/4=50π radian/second square Using the equation S=ut +1/2at^2 We get S=nn(2π) N=225 revolutions