A district contains 64000 inhabitants. If the population increases at the raye of 5/2%per annum, find the number of inhabitants at the end of the 3 years

2,75,684
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Initial Population (IP) = 64000
Rate (r) = 2.5% per annum
Time (n) = 3years

At the end of 3 years:
Population = IP * (1+r/100)^n
????????????????? = 64000*(1+2.5/100)^3
????????????????? =64000* 1.025^3
????????????????? = 68921 people


by=himanshu yadav
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9th class maths 1st lesson come in video writing
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