a dog chases a rabbit. The dog takes 6 leaps for every 7 leaps of the rabbit. The rabbit takes 6 leaps for every 5 leaps of the dog. Ratio of their speed is

Dear Student,

First we take the case of dog. We consider a unit time say 1 second. Now, in that time the dog takes 6 leaps.

6 leaps - 1 second

1 leap - 1/6 seconds.

So, for 5 leaps the time taken is 5/6 seconds.

 

Next, we take the example of the rabbit. Now it takes 7 leaps for dogs every 6 leaps.

So in the same time, i.e., 1 sec it will take 7 leaps.

7 leaps - 1 second.

1 leap - 1/7 seconds.

So, it will take 6 leaps in 6/7 seconds.

Now the same distance which d-meter is covered by dog in 5/6 seconds whereas by rabbit in 6/7 seconds.

 

So as speed = distance/time

 

speeddog / speedrabbit = (distancedog/timedog) / (distancerabbit/ timerabbit)

ratio = (d / {5/6} sec) / (d / {6/7} sec).

ratio of speeds = 36/35

Regards

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