A drunkard is walking along a straight road . he takes 5 steps forward and 3 steps backward, followed by 5 steps forward in 3 steps backward and so on .each step is 1 metre long and takes 1 seconds. there is a pit on the road 11 away from the Starting point. the drunkard will fall into the pit after (answer is 29 s)

For ?8 total steps it takes 8 seconds,

and moves in total 2 steps forward (2 m)?
Therfore,
3*2 m = 6 m?
At 3rd cycle Time Elapsed ?24 s?
After walking 5 m forward, he takes 5 s more.

It becomes 11 m.?
Time = 24 + 5 = 29m
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Net distance covered in 8s = 2m At the end of 24s , he will be 6m away from the starting point and 5m away from the pit. Now , again he will take 5 steps forward And , as soon as he will take the fifth step , he will fall into the pit So , total time : 24+5= 29s
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yes thx so much
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  • 33
29 s

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