a first order reaction is 20% complete in 10 minutes. calculate the time required for the completion of 75% of the reaction.
k = log
So, when 20% reaction is completed, then 80% reactants are left unreacted.
And, t = 10 min = 600s. Let, the initial concentration of reactants be 100 = [Ro]
So, k = log-4
When the reaction is 75% completed, then 25% reactants are left unreacted.
So, k = log. Thus, t = log
t = log
t = 0.372 x 104 s