a flight was scheduled to go from delhi to mumbai covering 1200 km but to engine problem its speed was reduced to 3/4th of the original. therefore it reached the destination 60 min late. what is the original speed and original time of the journey?

speed 400 time 3 hours
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how did u get
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let speed be x time be y
AQ
xy= 1200,x=1200/y
again
3x/4(y+1)=1200
3.1200(y+1)=4800
3(y+1)=4
y=3
x=1200/3=400 answer
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solved above
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Wrong way to solve he didn't even made quadratic equation
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