a force applied on a body of mass 4kg for 5 seconds changes its velocity from 10m/s to 20m/s find the power required
Given; Work done = Force applied * Displacement achieved
So W = F * s = change in Kinetic Energy (K.E) = ½ * m * (v2 - u2);
= ½ * 4 * ((202) - (102)) = 2(300) = 600 J
Power achieved = Work done / Time taken;
So P = W / t = 600 / 5 = 120 Watts of power is the answer;
Cheers!
So W = F * s = change in Kinetic Energy (K.E) = ½ * m * (v2 - u2);
= ½ * 4 * ((202) - (102)) = 2(300) = 600 J
Power achieved = Work done / Time taken;
So P = W / t = 600 / 5 = 120 Watts of power is the answer;
Cheers!