A force F=2xi +2yj + 3z2 k N is acting on a particle. Find the Work done by this force in displacing the body from (1,2,3)m to (3,6,1)m?

Dear  Student ,
Here the work done by this force in displacing the body is ,
W=F·dr=13Fxdx+26Fydy+31Fzdz=132xdx+262ydy+313z2dz=2x2213+2y2226+3z3331=8+32-8=32 J
Regards

  • -35
Here we have to integrate force*displacement from required limits
  • 3
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