A force F = (4i - 5j +3k )N is acting at a point having a position vector r1=(i+2j+3k) .The torgue acting about a point having a position vector r2 = (3i-2j-3k)is


Dear Student ,
                        torque=force×displacement from the axis of rotationso  torque=(4i-5j+3k^)×(i+2j+3k^)-(3i-2j-3k^)             =(4i-5j+3k^)×(-2i+4j+6k^)              =((-30-12)i-(24-6)j+(16+10)k^)              =(-42i+30j+26k^)Nm
Regard

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