A force F = (4i - 5j +3k )N is acting at a point having a position vector r1=(i+2j+3k) .The torgue acting about a point having a position vector r2 = (3i-2j-3k)is Share with your friends Share 1 Vijay Shankar Yadav answered this Dear Student , torque=force×displacement from the axis of rotationso torque=(4i→-5j→+3k^)×(i→+2j→+3k^)-(3i→-2j→-3k^) =(4i→-5j→+3k^)×(-2i→+4j→+6k^) =((-30-12)i→-(24-6)j→+(16+10)k^) =(-42i→+30j→+26k^)Nm Regard -4 View Full Answer