A force F→=i^+4j^ acts on block shown The force of friction acting on the block is: (A) –i^ - Physics - Laws Of Motion

Question

A force F → = i ^ + 4 j ^ acts on block shown The force of
friction acting on the block is:

(A) – i ^ (B) - 1 8 i ^ (C) - 2 4 i ^ (D) - 3 i ^

Shobhit Mittal · Accepted Answer

Dear Student,

normal rxn N=g-1=10-4=6 N maximum force of friction fmax=0
3*6=1
8 N the applied force on the block in x direction is 1N which is less than 1
8 N hence block will not move 
 the force of friction is equal to the applied force in x direction 
f=-i^option Regards

A force F → = i ^ + 4 j ^ acts on block shown.The force of friction acting on the block is: (A) – i ^ (B) - 1 . 8 i ^ (C) - 2 . 4 i ^ (D) - 3 i ^

A force $\vec{F} = \hat{i} + 4 \hat{j}$ acts on block shown.The force of friction acting on the block is:

(A) $- \hat{i}$ (B) $- 1.8 \hat{i}$ (C) $- 2.4 \hat{i}$ (D) $- 3 \hat{i}$