A force of 10N acts for 20sec on a body of mass 2kg 7nitaially at rest . Calculate the energy required by the body and the work done by the applied force .

Dear Student,acceleration produced in the body will be given by,a= forcemassa=102=5m/s2Initial velocity(u)=0 (given)time=20 secFinal velocity(v)= u+atv=0+5×20=100m/sEnergy required by the body= 12mv2-12mu2Energy required by the body=12×2×(100)2 Energy required by the body=104JoulesWork done by force= F×ss= distance covered by the bodys=ut+12at2s=o+12×5×20×20s=1000mWork done by the force= 10×1000=104JoulesHere we can see that work done by the force is equal to the energy gained by body, thus confirming law of conservation of energy.Regards

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