| A force of 12 N is applied to pull a block resting on a smooth surface of mass 5 kg by a rope of mass 0.6 kg. |
What is the force of reaction exerted by the block on the rope?
Let a be the total acceleration of the system.
F = 12 = (5+0.6)xa
a = 2.14m/s2
Therefore , force of reaction exerted by the block on the rope is,
= 5a = 10.7 N