A galvanic cell is constructed with Ag+?Ag and Fe3+?Fe2+ electrodes. Find the concentration of Ag+ at which the emf of the cell is zero at equimolar concentration of Fe2+ and Fe3+. E*Ag+/Ag= 0.80V and E*Fe3+/Fe2+= 0.77V

The given cell isAnode: Fe2+  Fe3+ + e-Cathode: Ag+ + e-  Ag--------------Fe2+ + Ag+ Fe3+ + Ag------------E0 = EFe2+/Fe3+0 +  EAg+/Ag0    = - 0.77 + 0.80    = 0.03 VGiven that E =0E = E0 - 0.0591n log [RHS][LHS]becomesE0 = 0.0591n log [RHS][LHS]  0.03  = 0.05911 log [Fe3+] [Ag][Fe2+] [Ag+]0.03 = 0.05911 log 1 [Ag+]   {since the concentration of [Ag]= 1 and [Fe2+] = [Fe3+] }0.03 = 0.05911 log  [Ag+]-10.03 = - 0.0591 log  [Ag+] log  [Ag+] = - 0.03 0.0591      = - 0.5076[Ag+] = A.log [- 0.5076]     = 0.3107

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