A gas absorbs a photon of 355 nm and emits at two wavelengths.If one of the emissions is at 680 nm,the other is at ???

We know,
E = hcλWhereE is energyh is Planck's constantc is speed of lightλ is wavelength

According to law of conservation of energy,
hc355  = hc680+ hcλ2Therefore,680 - 355355 x 680=1λ2λ2 = 742.77 nm
  = 743 nm

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