A gas absorbs a photon of 355 nm and emits at two wavelengths.If one of the emissions is at 680 nm,the other is at ??? Share with your friends Share 7 Anuradha Puri answered this We know, E = hcλWhereE is energyh is Planck's constantc is speed of lightλ is wavelength According to law of conservation of energy, hc355 = hc680+ hcλ2Therefore,680 - 355355 x 680=1λ2λ2 = 742.77 nm = 743 nm 34 View Full Answer