# A gaseous mixture contains 60% nitrogen , 15% oxygen and 25% carbon dioxide by mass . Calculate the mole fraction of each gas . plzz answer fasttttttt .................. plzzzzzzzzzzzzzzz

Molar mass of oxygen gas = 32 g

Molar mass of carbon dioxide gas = 44 g

Given mass of nitrogen = 60 g

Given mass of oxygen = 15 g

Given mass of carbon dioxide = 25 g

Number of moles (n) = $\frac{\text{Givenmass}}{\text{Molarmass}}$

${n}_{{N}_{2}}=\frac{60}{28}$ = 2.1428 moles

${\text{n}}_{{O}_{2}}=\frac{15}{32}$ = 0.468 moles

${\text{n}}_{C{O}_{2}}\text{=}\frac{25}{44}$ = 0.568 moles

Total number of moles = 2.1428 + 0.468 + 0.568 = 3.1788 moles

Mole fraction of N

_{2}= $\frac{2.1428}{3.1788}=0.674$

Mole fraction of O

_{2}= $\frac{0.468}{3.1788}=0.1472$

Mole fraction of CO

_{2}= $\frac{0.568}{3.1788}=0.1786$

**
**