A gaseous mixture contains 60% nitrogen , 15% oxygen and 25% carbon dioxide by mass . Calculate the mole fraction of each gas . plzz answer fasttttttt .................. plzzzzzzzzzzzzzzz

Molar mass of nitrogen gas = 28 g
Molar mass of oxygen gas = 32 g
Molar mass of carbon dioxide gas = 44 g
Given mass of nitrogen = 60 g
Given mass of oxygen = 15 g
Given mass of carbon dioxide = 25 g
Number of moles (n)  = Given massMolar mass
nN2 = 6028  = 2.1428 moles
nO2 = 1532 = 0.468 moles
nCO2 = 2544 = 0.568 moles
Total number of moles = 2.1428 + 0.468 + 0.568 = 3.1788 moles

Mole fraction of N2 = 2.14283.1788 = 0.674 
Mole fraction of O20.4683.1788 = 0.1472 
Mole fraction of CO2 = 0.5683.1788 = 0.1786

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I think , not sure , this question is incomplete. Quantity of elements ? 
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Sorry brother but these are the only information provided in the question .......... it seems too difficult to solve this
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i think a)6/100=6/10 b)15/100 c)25/100
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its not tenth class chemistry muskan .......... its the word problem of eleventh class ' chemistry grow up and i m very sorry to inform u that u r absolutely wrong my sis. ,,,,,,,,,
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From where you ask this question?
which book? ....
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No. of moles of N = 4.289 moles
No. of moles of O = 0.936 moles
No. of moles of CO2 = 0.568 moles
By applying Mole Fraction formula we get ,
Mole Fraction of N = 0.74024
Mole Fraction of O = 0.1617
Mole Fraction of CO2 = 0.0981

Tell me whether this answer is correct or not.
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If i know the correct solution and answer then why have i posted it here my brother.................... actually it was asked in a class test of mine and anybody from my class was not able to do this and i m a little bit confused about the answer provided by my teacher ............................ i request the experts to plz ans my ques fast plzzzzzzzz its very urgent  ................ i m going to hav another test of this lesson tomorrow ....................  so plzzz experts provide me the correct solution as fast as you can its my humble request ...................... plzzzzzzzzzzzzzzz
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Okay , I will ask this question to my tutor and telling you later in evening.
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ThanQ soo much brother its so nice of you :-)
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Composition of N2 = 60%
Composition of O2 = 15%
Composition of CO2 = 25%

1. Conversion of mass per cent to grams.

Since we are having mass per cent, it is convenient to use 100g of the compound as the starting material. Thus, in the 100 g sample of the above compound, 60 g Nitrogen is present , 15 g Oxygen is present and 25 g Carbon dioxide is present.

2. Convert into number moles of each element.

Divide the masses obtained above by respective atomic masses of various elements.

Moles of N2 = 60/28=2.143 moles
Moles of O2 = 15/32 = 0.469 moles
Moles of CO2=25/44 =0.568 moles

Now , by applying Mole Fraction formula we get,

Mole Fraction of N = 0.674
Mole Fraction of O = 0.147
Mole Fraction of CO2 = 0.179
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