A given number of atoms No of a radioactive element with a half life T is uniformly distributed in the blood stream of a
(i) normal person A having total volume V of blood in the body
(ii) person B in need of blood transfusion having a volume 𝑉′ of blood in the body.
The number of radioactive atoms per unit volume in the blood streams of the two persons after a time nT are found to be N1 and N2.
Prove mathematically that the additional volume of blood that needs to be transfused in the body of person B equals

Pre requisite:
Equation of Nuclear decay:
N=N0e-kt
Where
N0=Initial number of atomsN= Number of atoms at any given instant of timek=decay constant
The above relation can also be written as
N=N02-tT1/2
where
T1/2= Half life period

 

Given
                                        Person A                             Person B
Volume                                 V                                        V'
Initial                                                           
number of                                                    
atoms per                            NV                                         0
unit volume 
before transfusion

Final
Number of                            N1                                       N2
atoms per
unit volume

 

Consider the volume of blood transfused is x
Then the number of present in the transfused blood is NVx
Then the
Number of atoms present in the blood of person B after transfusion is NVx
Volume of the blood in person B is V'+x
Thus the number of atoms per unit volume is NxVV'+x

After a time of nT,
Number of atoms per unit volume in person A
N1=NV2-nTTN1=NV2-n

Number of atoms per unit volume in person B
N2=NxVV'+x2-nTTN2=NxVV'+x2-n


Hence
N1N2=V'+xx
Now solve for x
N1N2=V'x+1V'x=N1N2-1V'x=N1-N2N2x=N2V'N1-N2



 

  • 3
What are you looking for?