A graph between t 1 /2 and conc. for n th order reaction is a straight line. Reaction of this nature is completed 50% in 10 minutes when conc. is 2 mol L–1. This is decomposed 50% in t minutes at 4 mol L–1, n and t are respectively


(1) 0, 20 min.          (2) 1, 10 min.             (3) 1, 20 min.                 (4) 0, 5 min.

Dear student,
From the graph, it is clear that t1/2 is independent of concentration. Hence reaction is of first order (For first order reaction t1/2=0.693/k)
Due to the fact that t1/2 is independent of initial concentration, it will remain  same whether concentration is 2 or 4 molL-1​Thus time required for completion of reaction = 2*t1/2 = 2*10 = 20 min
Hence, n=1 and t=20 min
Option 3 is correct
Regards

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