A helium nucleus is completing one round of a circle of radius 0.8m in 2 seconds. Compute the magnetic field at the centre of circle.

Dear Student,

The expression for the magnetic field for an electron revolving around a nucleus is given as,
As the number of rotation is 1 there we have,
we know that current is defined as charge per unit time (I=qt) and for helium atom there are only two charges therefore the current for helium nucleus is given as,
On substituting the above equation in magnetic field equation we get,
On substituting the values we get,
 B=1.67×10-19 C0.8 m×2 sμo B=1×10-19×μo
Thus, the magnetic field at the centre of the circle is
B = μ​​​​​​o × 10-19 T 


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