A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm, find the outer curved surface area of the bowl. (Take pie=3.14)
Inner radius of hemispherical bowl = 5 cm
Thickness of the bowl = 0.25 cm
∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm
= 5.25 cm
Outer CSA of hemispherical bowl = 2πr2
Therefore, the outer curved surface area of the bowl is 173.25 cm2.