A Hydraulic presswith a larger piston of diameter 30cm at a height 1m above the smaller piston of diameter 5cm is present.The mass on the Smaller piston is 10kg . What is the force exerted on the Load by the larger piston . (Density of Oil = 750kgm^-3

Pressure:

It is the force acting normally per unit area.

Pressure on the larger piston is equal to the pressure on the smaller piston + liquid pressure:

          F1A1=F2A2+ρghF1πr12=mgπr22+ρghF1=πr12mgπr22+ρgh     =π15×10-3210×9.8π×2.5×10-32+750×9.8×1     =3533.2 N     

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