A hydroelectric power station takes its wat)er from a lake whose water level is 50 m above the turbine. Assuming an overall efficiency of 40%, calculate the mass of water which must flow through the turbine each second to produce power output of 1MW. (g=10 m/s2)
Here we will use the following formula
P = E/t
where P is the power
as it has an efficiency of 40 % than available power = 0.4MW = 400000 W
E is the potential energy = m X g X h
here g = 10 m/s
h = 50 m
and also t = 1 sec
thus,
E = P X t = P
mgh = P
m = P/gh
or m = 400000 / 10 X 50
thus, the mass of water flowing = 800 kg