# A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure, The oxidation potential of electrode would be1- 0.59V 2- 0.118V3- 1.18V 4- 0.059V

Ans is - 0.59 V

As pH = 10

and pH = - log[H+]

10 = - log[H+]

[H+] = ${10}^{-10}$

Now according to Nernst equation,

Ecell​ = Eocell -

Half cell reaction is

H+(aq)  +   e- $\to$ $\frac{1}{2}{H}_{2}$ (g)

Thus n = 1 and

Now for this reaction E0cell = 0 V

So   Ecell = 0 - 0.0591 log(1/10-10)

= - 0.0591 log 1010

​= - 0.0591 x 10
​Ecell = - 0.591 V
The correct option is (1).

• 53
What are you looking for?