a hypermetropic eye is corrected for near vision by lens of power 8/3 cal how is the near point of - Science - The Human Eye and the Colourful World

Question

a hypermetropic eye is corrected for near vision by lens of power
8/3 cal how is the near point of defective eye

Pintu B. · Accepted Answer

Dear Student ,

Distance of the object for eye lens = Distance of normal near
point, u = – 25 cm
Distance of the image from eye lens = Near point of
hypermetropic eye v = ?
Power of lens = 8/3 = 100 /f
f = 37 5 cm
Now from the len's maker's equation we can write that ,
1f=1v-1u⇒137 5 -125=1v⇒v = -75 cm
Regards

a hypermetropic eye is corrected for near vision by lens of power 8/3 cal how is the near point of defective eye