# A jar contains two immiscible liquids A and B with a coin at its bottom. The depths of liquid A and liquid B are 6 cm and 8 cm respectively. If the apparent depth of the coin is 9 cm and the refractive index of liquid A is 1.5, than what is the refractive index of liquid B ?

Dear Student,

For refractive index,
For liquid A, apparent depth =
For liquid B, apparent depth =
Total apparent depth, = $\frac{6}{1.5}+\frac{8}{x}=9$
$\frac{6}{1.5}+\frac{8}{x}=9\phantom{\rule{0ex}{0ex}}⇒\frac{6x+12}{1.5x}=9\phantom{\rule{0ex}{0ex}}⇒6x+12=13.5x\phantom{\rule{0ex}{0ex}}⇒7.5x=12\phantom{\rule{0ex}{0ex}}⇒x=\frac{12}{7.5}=1.6\phantom{\rule{0ex}{0ex}}$
thus, refractive index of B is 1.6.

Regards

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