A jar contains two immiscible liquids A and B with a coin at its bottom. The depths of liquid A and liquid B are 6 cm and 8 cm respectively. If the apparent depth of the coin is 9 cm and the refractive index of liquid A is 1.5, than what is the refractive index of liquid B ?

Dear Student, 

For refractive index, μ=real depth apparent depth 
For liquid A, apparent depth = real depth refractive index =61.5
For liquid B, apparent depth = real depth refractive index =8x
Total apparent depth, = 61.5+8x=9
61.5+8x=96x+121.5x=96x+12=13.5x7.5x=12x=127.5=1.6
thus, refractive index of B is 1.6.

Regards 
 

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