^{-1}. if the horizontal component of earth's magnetic field at that place is 4 * 10^{-4} Tesla and the angle of dip is 30 degrees, find the emf induced between the ends of the wings having span of 30 m.

let velocity of plane **v** = 450 m/s.

wingspan **l** = 30 m.

mag. Field **B** = 4 × 10^{-4 }T

angle of dip **α** = 30^{∙ }

therefore vertical component **B _{v}**

_{ }=

**B**sin

**α**

= 4 × 10^{-4 }× sin 30^{∙ }

**B _{v}** = 2 × 10

^{-4 }T

Motional EMF **ε** = **B _{v}**

**l**

**v**

= 2 × 10^{-4 } × 30 × 450

= 27000 × 10^{-4 }

ε = 2.7 Volts