A ladder 10m long was rested along a wall such that its top reaches to a height of 8m from the ground along the wall. How far is the foot of the ladder from the wall ?



Let AC be the ladder and AB be the wall.Now, AB = 8 m; AC = 10 mIn ABC,    AC2 = AB2 + BC2    Pythagoras theorem102 = 82 + BC2100 = 64 + BC2BC2 = 100-64BC2 = 36BC = 6 mSo, foot of the ladder is 6 m away from the wall.

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Please answer fastly
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We will use Pythagoras theoram in this question...
We know that,
h2= p2+b2
100= 64+b2
100-64= b2
36= b2
?36= b
6= b
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