a ladder 16m long reaches a window which is 9m above the ground on one side of the street keeping,its foot at the same point the ladder is turn to the other side of the street to reach a window 12m high .find the width of th street.
In Δ ABC, apply Pythagoras theorem
AC2 = AB2 + BC2
⇒ (16)2 = (9)2 + (BC)2
⇒ 256 = 81 + (BC)2
⇒ (BC)2 = 175m
⇒ BC = m
Now In Δ CED, apply Pythagoras theorem
CE2 = ED2 + CD2
⇒ (16)2 = (12)2 + CD2
⇒ 256 = 144 + CD2
⇒ CD = m
∴ Width of the street = BC + CD = +
m =