A ladder 5 m long is leaning against a wall. The bottom of the ladder is pulled along the ground, away from the wall, at the rate of 2 cm/s. How fast is its height on the wall decreasing when the foot of the ladder is 4 m away from the wall?

Let
*y* m be the
height of the wall at which the ladder touches. Also, let the foot of
the ladder be *x *maway from the wall.

Then, by Pythagoras theorem, we have:

*x*^{2}
+ *y*^{2}
= 25 [Length of the ladder = 5 m]

Then,
the rate of change of height (*y)*
with respect to time (*t)*
is given by,

It is given that.

Now,
when *x* = 4
m, we have:

Hence, the height of the ladder on the wall is decreasing at the rate of.

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